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13427000941 is a prime number
BaseRepresentation
bin11001000000100111…
…11100011001101101
31021122202021022122011
430200103330121231
5204444303012231
610100203121221
7653506424224
oct144023743155
937582238564
1013427000941
1157702125a2
122728813211
13135c9a8193
1491535bcbb
15538b9a9b1
hex3204fc66d

13427000941 has 2 divisors, whose sum is σ = 13427000942. Its totient is φ = 13427000940.

The previous prime is 13427000893. The next prime is 13427000963. The reversal of 13427000941 is 14900072431.

13427000941 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8221955625 + 5205045316 = 90675^2 + 72146^2 .

It is a cyclic number.

It is not a de Polignac number, because 13427000941 - 215 = 13426968173 is a prime.

It is a super-2 number, since 2×134270009412 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13427000341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6713500470 + 6713500471.

It is an arithmetic number, because the mean of its divisors is an integer number (6713500471).

Almost surely, 213427000941 is an apocalyptic number.

It is an amenable number.

13427000941 is a deficient number, since it is larger than the sum of its proper divisors (1).

13427000941 is an equidigital number, since it uses as much as digits as its factorization.

13427000941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 31.

The spelling of 13427000941 in words is "thirteen billion, four hundred twenty-seven million, nine hundred forty-one", and thus it is an aban number.