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13427055583 = 171495300851
BaseRepresentation
bin11001000000101000…
…01001101111011111
31021122202101002120221
430200110021233133
5204444311234313
610100204222211
7653510042434
oct144024115737
937582332527
1013427055583
11577024a657
12272883a967
13135c9c7006
14915373b8b
15538babc8d
hex320509bdf

13427055583 has 8 divisors (see below), whose sum is σ = 14312300400. Its totient is φ = 12552412800.

The previous prime is 13427055581. The next prime is 13427055619. The reversal of 13427055583 is 38555072431.

13427055583 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13427055583 - 21 = 13427055581 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13427055581) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2647893 + ... + 2652958.

It is an arithmetic number, because the mean of its divisors is an integer number (1789037550).

Almost surely, 213427055583 is an apocalyptic number.

13427055583 is a deficient number, since it is larger than the sum of its proper divisors (885244817).

13427055583 is a wasteful number, since it uses less digits than its factorization.

13427055583 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5301017.

The product of its (nonzero) digits is 504000, while the sum is 43.

The spelling of 13427055583 in words is "thirteen billion, four hundred twenty-seven million, fifty-five thousand, five hundred eighty-three".

Divisors: 1 17 149 2533 5300851 90114467 789826799 13427055583