13428000581 has 2 divisors, whose sum is σ = 13428000582. Its totient is φ = 13428000580.

The previous prime is 13428000559. The next prime is 13428000583. The reversal of 13428000581 is 18500082431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10228288225 + 3199712356 = 101135^2 + 56566^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13428000581 is a prime.

It is a super-2 number, since 2×13428000581² (a number of 21 digits) contains 22 as substring.

Together with 13428000583, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13428000583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6714000290 + 6714000291.

It is an arithmetic number, because the mean of its divisors is an integer number (6714000291).

Almost surely, 2^13428000581 is an apocalyptic number.

It is an amenable number.

13428000581 is a deficient number, since it is larger than the sum of its proper divisors (1).

13428000581 is an equidigital number, since it uses as much as digits as its factorization.

13428000581 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7680, while the sum is 32.

The spelling of 13428000581 in words is "thirteen billion, four hundred twenty-eight million, five hundred eighty-one", and thus it is an aban number.