Base | Representation |
---|---|
bin | 1100001101101001101101… |
… | …0110110010100100000010 |
3 | 1202112202202101122200201221 |
4 | 3003122123112302210002 |
5 | 3230003411044210200 |
6 | 44321014152345254 |
7 | 2554122031305421 |
oct | 303323326624402 |
9 | 52482671580657 |
10 | 13428674210050 |
11 | 4308083563550 |
12 | 160a6979a522a |
13 | 76541aac3c48 |
14 | 345d4651b2b8 |
15 | 18449d5c291a |
hex | c369b5b2902 |
13428674210050 has 96 divisors (see below), whose sum is σ = 27395198541504. Its totient is φ = 4856785920000.
The previous prime is 13428674210033. The next prime is 13428674210087. The reversal of 13428674210050 is 5001247682431.
It is a junction number, because it is equal to n+sod(n) for n = 13428674209979 and 13428674210006.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 608971525 + ... + 608993575.
It is an arithmetic number, because the mean of its divisors is an integer number (285366651474).
Almost surely, 213428674210050 is an apocalyptic number.
13428674210050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13428674210050 is an abundant number, since it is smaller than the sum of its proper divisors (13966524331454).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13428674210050 is a wasteful number, since it uses less digits than its factorization.
13428674210050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28004 (or 27999 counting only the distinct ones).
The product of its (nonzero) digits is 322560, while the sum is 43.
The spelling of 13428674210050 in words is "thirteen trillion, four hundred twenty-eight billion, six hundred seventy-four million, two hundred ten thousand, fifty".
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