Base | Representation |
---|---|
bin | 111110100010011101… |
… | …0000011011101110111 |
3 | 110211122121020200201111 |
4 | 1331010322003131313 |
5 | 4200021303233130 |
6 | 141410244135451 |
7 | 12463036431031 |
oct | 1750472033567 |
9 | 424577220644 |
10 | 134300055415 |
11 | 51a57975439 |
12 | 22040997587 |
13 | c883a13316 |
14 | 6700608c51 |
15 | 376060902a |
hex | 1f44e83777 |
134300055415 has 4 divisors (see below), whose sum is σ = 161160066504. Its totient is φ = 107440044328.
The previous prime is 134300055371. The next prime is 134300055427. The reversal of 134300055415 is 514550003431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 514550003431 = 2027 ⋅253848053.
It is a cyclic number.
It is not a de Polignac number, because 134300055415 - 223 = 134291666807 is a prime.
It is a super-3 number, since 3×1343000554153 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13430005537 + ... + 13430005546.
It is an arithmetic number, because the mean of its divisors is an integer number (40290016626).
Almost surely, 2134300055415 is an apocalyptic number.
134300055415 is a deficient number, since it is larger than the sum of its proper divisors (26860011089).
134300055415 is an equidigital number, since it uses as much as digits as its factorization.
134300055415 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26860011088.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 134300055415 its reverse (514550003431), we get a palindrome (648850058846).
The spelling of 134300055415 in words is "one hundred thirty-four billion, three hundred million, fifty-five thousand, four hundred fifteen".
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