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1343014120453 is a prime number
BaseRepresentation
bin10011100010110001111…
…000010010110000000101
311202101112222000011200111
4103202301320102300011
5134000443103323303
62504545553313021
7166013066445355
oct23426170226005
94671488004614
101343014120453
11478629505575
12198350865771
1399851766415
1449006196b65
1524e0533eb6d
hex138b1e12c05

1343014120453 has 2 divisors, whose sum is σ = 1343014120454. Its totient is φ = 1343014120452.

The previous prime is 1343014120439. The next prime is 1343014120457. The reversal of 1343014120453 is 3540214103431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1272027576964 + 70986543489 = 1127842^2 + 266433^2 .

It is a cyclic number.

It is not a de Polignac number, because 1343014120453 - 225 = 1342980566021 is a prime.

It is a super-2 number, since 2×13430141204532 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1343014120457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671507060226 + 671507060227.

It is an arithmetic number, because the mean of its divisors is an integer number (671507060227).

Almost surely, 21343014120453 is an apocalyptic number.

It is an amenable number.

1343014120453 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343014120453 is an equidigital number, since it uses as much as digits as its factorization.

1343014120453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1343014120453 its reverse (3540214103431), we get a palindrome (4883228223884).

The spelling of 1343014120453 in words is "one trillion, three hundred forty-three billion, fourteen million, one hundred twenty thousand, four hundred fifty-three".