Base | Representation |
---|---|
bin | 1100001101110000101001… |
… | …0010010010010000000111 |
3 | 1202112221120002121212100011 |
4 | 3003130022102102100013 |
5 | 3230021214014100403 |
6 | 44321522554131051 |
7 | 2554216120310065 |
oct | 303341222222007 |
9 | 52487502555304 |
10 | 13430535300103 |
11 | 4308949052aa9 |
12 | 160ab17120a87 |
13 | 76565655316c |
14 | 346081777035 |
15 | 18455bb96a6d |
hex | c370a492407 |
13430535300103 has 4 divisors (see below), whose sum is σ = 13430817330040. Its totient is φ = 13430253270168.
The previous prime is 13430535300073. The next prime is 13430535300173. The reversal of 13430535300103 is 30100353503431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13430535300103 - 225 = 13430501745671 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13430535300173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140943525 + ... + 141038782.
It is an arithmetic number, because the mean of its divisors is an integer number (3357704332510).
Almost surely, 213430535300103 is an apocalyptic number.
13430535300103 is a deficient number, since it is larger than the sum of its proper divisors (282029937).
13430535300103 is an equidigital number, since it uses as much as digits as its factorization.
13430535300103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 282029936.
The product of its (nonzero) digits is 24300, while the sum is 31.
Adding to 13430535300103 its reverse (30100353503431), we get a palindrome (43530888803534).
The spelling of 13430535300103 in words is "thirteen trillion, four hundred thirty billion, five hundred thirty-five million, three hundred thousand, one hundred three".
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