Base | Representation |
---|---|
bin | 111110100010110001… |
… | …1111011011001111101 |
3 | 110211200100220101101011 |
4 | 1331011203323121331 |
5 | 4200032111014240 |
6 | 141411315315221 |
7 | 12463231640032 |
oct | 1750543733175 |
9 | 424610811334 |
10 | 134311032445 |
11 | 51a63092667 |
12 | 220445abb11 |
13 | c8860877c5 |
14 | 6701c65389 |
15 | 37615766ea |
hex | 1f458fb67d |
134311032445 has 4 divisors (see below), whose sum is σ = 161173238940. Its totient is φ = 107448825952.
The previous prime is 134311032437. The next prime is 134311032533. The reversal of 134311032445 is 544230113431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 62149492804 + 72161539641 = 249298^2 + 268629^2 .
It is a cyclic number.
It is not a de Polignac number, because 134311032445 - 23 = 134311032437 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13431103240 + ... + 13431103249.
It is an arithmetic number, because the mean of its divisors is an integer number (40293309735).
Almost surely, 2134311032445 is an apocalyptic number.
It is an amenable number.
134311032445 is a deficient number, since it is larger than the sum of its proper divisors (26862206495).
134311032445 is an equidigital number, since it uses as much as digits as its factorization.
134311032445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26862206494.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 134311032445 its reverse (544230113431), we get a palindrome (678541145876).
The spelling of 134311032445 in words is "one hundred thirty-four billion, three hundred eleven million, thirty-two thousand, four hundred forty-five".
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