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134311032445 = 526862206489
BaseRepresentation
bin111110100010110001…
…1111011011001111101
3110211200100220101101011
41331011203323121331
54200032111014240
6141411315315221
712463231640032
oct1750543733175
9424610811334
10134311032445
1151a63092667
12220445abb11
13c8860877c5
146701c65389
1537615766ea
hex1f458fb67d

134311032445 has 4 divisors (see below), whose sum is σ = 161173238940. Its totient is φ = 107448825952.

The previous prime is 134311032437. The next prime is 134311032533. The reversal of 134311032445 is 544230113431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 62149492804 + 72161539641 = 249298^2 + 268629^2 .

It is a cyclic number.

It is not a de Polignac number, because 134311032445 - 23 = 134311032437 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13431103240 + ... + 13431103249.

It is an arithmetic number, because the mean of its divisors is an integer number (40293309735).

Almost surely, 2134311032445 is an apocalyptic number.

It is an amenable number.

134311032445 is a deficient number, since it is larger than the sum of its proper divisors (26862206495).

134311032445 is an equidigital number, since it uses as much as digits as its factorization.

134311032445 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26862206494.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 134311032445 its reverse (544230113431), we get a palindrome (678541145876).

The spelling of 134311032445 in words is "one hundred thirty-four billion, three hundred eleven million, thirty-two thousand, four hundred forty-five".

Divisors: 1 5 26862206489 134311032445