13431240401023 has 4 divisors (see below), whose sum is σ = 13521382954200. Its totient is φ = 13341097847848.

The previous prime is 13431240401003. The next prime is 13431240401027. The reversal of 13431240401023 is 32010404213431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13431240401023 - 2⁹ = 13431240400511 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13431240400982 and 13431240401000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13431240401027) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45071276365 + ... + 45071276662.

It is an arithmetic number, because the mean of its divisors is an integer number (3380345738550).

Almost surely, 2^{13431240401023} is an apocalyptic number.

13431240401023 is a deficient number, since it is larger than the sum of its proper divisors (90142553177).

13431240401023 is an equidigital number, since it uses as much as digits as its factorization.

13431240401023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 90142553176.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 13431240401023 its reverse (32010404213431), we get a palindrome (45441644614454).

The spelling of 13431240401023 in words is "thirteen trillion, four hundred thirty-one billion, two hundred forty million, four hundred one thousand, twenty-three".