Base | Representation |
---|---|
bin | 10011100010111000011… |
… | …011111111110000000111 |
3 | 11202101211122000220101202 |
4 | 103202320123333300013 |
5 | 134001204240034421 |
6 | 2505004523413115 |
7 | 166015603563212 |
oct | 23427033776007 |
9 | 4671748026352 |
10 | 1343124143111 |
11 | 478685622193 |
12 | 19838168419b |
13 | 9986b4a8b9a |
14 | 49016a36779 |
15 | 24e0ed2410b |
hex | 138b86ffc07 |
1343124143111 has 4 divisors (see below), whose sum is σ = 1343182464000. Its totient is φ = 1343065822224.
The previous prime is 1343124143083. The next prime is 1343124143113. The reversal of 1343124143111 is 1113414213431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1343124143111 - 230 = 1342050401287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1343124143113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29125886 + ... + 29171963.
It is an arithmetic number, because the mean of its divisors is an integer number (335795616000).
Almost surely, 21343124143111 is an apocalyptic number.
1343124143111 is a deficient number, since it is larger than the sum of its proper divisors (58320889).
1343124143111 is an equidigital number, since it uses as much as digits as its factorization.
1343124143111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58320888.
The product of its digits is 3456, while the sum is 29.
Adding to 1343124143111 its reverse (1113414213431), we get a palindrome (2456538356542).
The spelling of 1343124143111 in words is "one trillion, three hundred forty-three billion, one hundred twenty-four million, one hundred forty-three thousand, one hundred eleven".
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