Base | Representation |
---|---|
bin | 111110100010110110… |
… | …1000111010010111111 |
3 | 110211200112102201112102 |
4 | 1331011231013102333 |
5 | 4200033220043242 |
6 | 141411443055315 |
7 | 12463261256324 |
oct | 1750555072277 |
9 | 424615381472 |
10 | 134313440447 |
11 | 51a6448784a |
12 | 2204537153b |
13 | c88671b864 |
14 | 67022d0b4b |
15 | 376189ee32 |
hex | 1f45b474bf |
134313440447 has 2 divisors, whose sum is σ = 134313440448. Its totient is φ = 134313440446.
The previous prime is 134313440407. The next prime is 134313440461. The reversal of 134313440447 is 744044313431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134313440447 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 134313440447.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134313440407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67156720223 + 67156720224.
It is an arithmetic number, because the mean of its divisors is an integer number (67156720224).
Almost surely, 2134313440447 is an apocalyptic number.
134313440447 is a deficient number, since it is larger than the sum of its proper divisors (1).
134313440447 is an equidigital number, since it uses as much as digits as its factorization.
134313440447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 193536, while the sum is 38.
Adding to 134313440447 its reverse (744044313431), we get a palindrome (878357753878).
The spelling of 134313440447 in words is "one hundred thirty-four billion, three hundred thirteen million, four hundred forty thousand, four hundred forty-seven".
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