Base | Representation |
---|---|
bin | 10011100010111001001… |
… | …010100101000000100101 |
3 | 11202101212111000022001112 |
4 | 103202321022211000211 |
5 | 134001220401314331 |
6 | 2505010041234405 |
7 | 166016112432365 |
oct | 23427112450045 |
9 | 4671774008045 |
10 | 1343136354341 |
11 | 478691502711 |
12 | 198385792a05 |
13 | 99870b93072 |
14 | 490184d49a5 |
15 | 24e10e3732b |
hex | 138b92a5025 |
1343136354341 has 2 divisors, whose sum is σ = 1343136354342. Its totient is φ = 1343136354340.
The previous prime is 1343136354337. The next prime is 1343136354389. The reversal of 1343136354341 is 1434536313431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1027275494116 + 315860860225 = 1013546^2 + 562015^2 .
It is a cyclic number.
It is not a de Polignac number, because 1343136354341 - 22 = 1343136354337 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1343136354641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671568177170 + 671568177171.
It is an arithmetic number, because the mean of its divisors is an integer number (671568177171).
Almost surely, 21343136354341 is an apocalyptic number.
It is an amenable number.
1343136354341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343136354341 is an equidigital number, since it uses as much as digits as its factorization.
1343136354341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 466560, while the sum is 41.
The spelling of 1343136354341 in words is "one trillion, three hundred forty-three billion, one hundred thirty-six million, three hundred fifty-four thousand, three hundred forty-one".
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