Base | Representation |
---|---|
bin | 111110100010111000… |
… | …0110010001000011011 |
3 | 110211200121020120222202 |
4 | 1331011300302020123 |
5 | 4200033441333311 |
6 | 141411515440415 |
7 | 12463302403544 |
oct | 1750560621033 |
9 | 424617216882 |
10 | 134314402331 |
11 | 51a64a8449a |
12 | 2204575610b |
13 | c886997615 |
14 | 67024a14cb |
15 | 37619dee3b |
hex | 1f45c3221b |
134314402331 has 2 divisors, whose sum is σ = 134314402332. Its totient is φ = 134314402330.
The previous prime is 134314402309. The next prime is 134314402441. The reversal of 134314402331 is 133204413431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134314402331 - 222 = 134310208027 is a prime.
It is a super-2 number, since 2×1343144023312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 134314402294 and 134314402303.
It is not a weakly prime, because it can be changed into another prime (134314402531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67157201165 + 67157201166.
It is an arithmetic number, because the mean of its divisors is an integer number (67157201166).
Almost surely, 2134314402331 is an apocalyptic number.
134314402331 is a deficient number, since it is larger than the sum of its proper divisors (1).
134314402331 is an equidigital number, since it uses as much as digits as its factorization.
134314402331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 134314402331 its reverse (133204413431), we get a palindrome (267518815762).
The spelling of 134314402331 in words is "one hundred thirty-four billion, three hundred fourteen million, four hundred two thousand, three hundred thirty-one".
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