Base | Representation |
---|---|
bin | 111110100010111000… |
… | …0110010001010001001 |
3 | 110211200121020121010211 |
4 | 1331011300302022021 |
5 | 4200033441334231 |
6 | 141411515441121 |
7 | 12463302404062 |
oct | 1750560621211 |
9 | 424617217124 |
10 | 134314402441 |
11 | 51a64a8458a |
12 | 220457561a1 |
13 | c88699769b |
14 | 67024a1569 |
15 | 37619deeb1 |
hex | 1f45c32289 |
134314402441 has 2 divisors, whose sum is σ = 134314402442. Its totient is φ = 134314402440.
The previous prime is 134314402331. The next prime is 134314402447. The reversal of 134314402441 is 144204413431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129971065225 + 4343337216 = 360515^2 + 65904^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134314402441 is a prime.
It is not a weakly prime, because it can be changed into another prime (134314402447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67157201220 + 67157201221.
It is an arithmetic number, because the mean of its divisors is an integer number (67157201221).
Almost surely, 2134314402441 is an apocalyptic number.
It is an amenable number.
134314402441 is a deficient number, since it is larger than the sum of its proper divisors (1).
134314402441 is an equidigital number, since it uses as much as digits as its factorization.
134314402441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 134314402441 its reverse (144204413431), we get a palindrome (278518815872).
The spelling of 134314402441 in words is "one hundred thirty-four billion, three hundred fourteen million, four hundred two thousand, four hundred forty-one".
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