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134322013541 is a prime number
BaseRepresentation
bin111110100011000110…
…1110100010101100101
3110211201010120021121102
41331012031310111211
54200042413413131
6141412350525445
712463424163632
oct1750615642545
9424633507542
10134322013541
1151a69302951
1222048206885
13c888430ab1
1467034c3189
1537624e51cb
hex1f46374565

134322013541 has 2 divisors, whose sum is σ = 134322013542. Its totient is φ = 134322013540.

The previous prime is 134322013421. The next prime is 134322013543. The reversal of 134322013541 is 145310223431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101599012516 + 32723001025 = 318746^2 + 180895^2 .

It is a cyclic number.

It is not a de Polignac number, because 134322013541 - 214 = 134321997157 is a prime.

Together with 134322013543, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134322013543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67161006770 + 67161006771.

It is an arithmetic number, because the mean of its divisors is an integer number (67161006771).

Almost surely, 2134322013541 is an apocalyptic number.

It is an amenable number.

134322013541 is a deficient number, since it is larger than the sum of its proper divisors (1).

134322013541 is an equidigital number, since it uses as much as digits as its factorization.

134322013541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 134322013541 its reverse (145310223431), we get a palindrome (279632236972).

The spelling of 134322013541 in words is "one hundred thirty-four billion, three hundred twenty-two million, thirteen thousand, five hundred forty-one".