Base | Representation |
---|---|
bin | 11110100010101011010001… |
… | …100001011100011001010111 |
3 | 122121121021112222112222122222 |
4 | 132202223101201130121113 |
5 | 120101232203014422221 |
6 | 1153403424123012555 |
7 | 40202416633616522 |
oct | 3642532141343127 |
9 | 577537488488588 |
10 | 134324322420311 |
11 | 398886971a6501 |
12 | 13094b5396a15b |
13 | 59c49632265aa |
14 | 2525490a07bb9 |
15 | 107e13d1909ab |
hex | 7a2ad185c657 |
134324322420311 has 2 divisors, whose sum is σ = 134324322420312. Its totient is φ = 134324322420310.
The previous prime is 134324322420269. The next prime is 134324322420329. The reversal of 134324322420311 is 113024223423431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134324322420311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134324322420331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67162161210155 + 67162161210156.
It is an arithmetic number, because the mean of its divisors is an integer number (67162161210156).
Almost surely, 2134324322420311 is an apocalyptic number.
134324322420311 is a deficient number, since it is larger than the sum of its proper divisors (1).
134324322420311 is an equidigital number, since it uses as much as digits as its factorization.
134324322420311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 134324322420311 its reverse (113024223423431), we get a palindrome (247348545843742).
The spelling of 134324322420311 in words is "one hundred thirty-four trillion, three hundred twenty-four billion, three hundred twenty-two million, four hundred twenty thousand, three hundred eleven".
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