Base | Representation |
---|---|
bin | 111110100011001101… |
… | …0010111111110011101 |
3 | 110211201100202111222101 |
4 | 1331012122113332131 |
5 | 4200044234231440 |
6 | 141412545245101 |
7 | 12463464153505 |
oct | 1750632277635 |
9 | 424640674871 |
10 | 134325305245 |
11 | 51a70150a6a |
12 | 22049333791 |
13 | c889014151 |
14 | 6703adca05 |
15 | 376294569a |
hex | 1f46697f9d |
134325305245 has 4 divisors (see below), whose sum is σ = 161190366300. Its totient is φ = 107460244192.
The previous prime is 134325305227. The next prime is 134325305269. The reversal of 134325305245 is 542503523431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 52970863716 + 81354441529 = 230154^2 + 285227^2 .
It is a cyclic number.
It is not a de Polignac number, because 134325305245 - 217 = 134325174173 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13432530520 + ... + 13432530529.
It is an arithmetic number, because the mean of its divisors is an integer number (40297591575).
Almost surely, 2134325305245 is an apocalyptic number.
It is an amenable number.
134325305245 is a deficient number, since it is larger than the sum of its proper divisors (26865061055).
134325305245 is an equidigital number, since it uses as much as digits as its factorization.
134325305245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26865061054.
The product of its (nonzero) digits is 216000, while the sum is 37.
Adding to 134325305245 its reverse (542503523431), we get a palindrome (676828828676).
The spelling of 134325305245 in words is "one hundred thirty-four billion, three hundred twenty-five million, three hundred five thousand, two hundred forty-five".
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