Base | Representation |
---|---|
bin | 10011100011000011000… |
… | …110011011110100101101 |
3 | 11202102022002122211012121 |
4 | 103203003012123310231 |
5 | 134002041034242201 |
6 | 2505034354032541 |
7 | 166023205306315 |
oct | 23430306336455 |
9 | 4672262584177 |
10 | 1343303040301 |
11 | 478767601302 |
12 | 198411578751 |
13 | 99899584b01 |
14 | 490326c4445 |
15 | 24e208b09a1 |
hex | 138c319bd2d |
1343303040301 has 8 divisors (see below), whose sum is σ = 1369354871808. Its totient is φ = 1317449322000.
The previous prime is 1343303040199. The next prime is 1343303040311. The reversal of 1343303040301 is 1030403033431.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1343303040301 - 213 = 1343303032109 is a prime.
It is a super-4 number, since 4×13433030403014 (a number of 50 digits) contains 4444 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1343303040311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49514610 + ... + 49541731.
It is an arithmetic number, because the mean of its divisors is an integer number (171169358976).
Almost surely, 21343303040301 is an apocalyptic number.
It is an amenable number.
1343303040301 is a deficient number, since it is larger than the sum of its proper divisors (26051831507).
1343303040301 is an equidigital number, since it uses as much as digits as its factorization.
1343303040301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 99056603.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 1343303040301 its reverse (1030403033431), we get a palindrome (2373706073732).
The spelling of 1343303040301 in words is "one trillion, three hundred forty-three billion, three hundred three million, forty thousand, three hundred one".
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