Base | Representation |
---|---|
bin | 10011100011000011100… |
… | …010001111100001111111 |
3 | 11202102022121101011202211 |
4 | 103203003202033201333 |
5 | 134002044421024413 |
6 | 2505035214201251 |
7 | 166023324260116 |
oct | 23430342174177 |
9 | 4672277334684 |
10 | 1343310329983 |
11 | 478770730136 |
12 | 198413ab3227 |
13 | 9989ac37b2b |
14 | 49033660c7d |
15 | 24e2135083d |
hex | 138c388f87f |
1343310329983 has 2 divisors, whose sum is σ = 1343310329984. Its totient is φ = 1343310329982.
The previous prime is 1343310329971. The next prime is 1343310330017. The reversal of 1343310329983 is 3899230133431.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (3899230133431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1343310329983 - 233 = 1334720395391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1343310329923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671655164991 + 671655164992.
It is an arithmetic number, because the mean of its divisors is an integer number (671655164992).
Almost surely, 21343310329983 is an apocalyptic number.
1343310329983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343310329983 is an equidigital number, since it uses as much as digits as its factorization.
1343310329983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1259712, while the sum is 49.
The spelling of 1343310329983 in words is "one trillion, three hundred forty-three billion, three hundred ten million, three hundred twenty-nine thousand, nine hundred eighty-three".
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