1343314244101 has 4 divisors (see below), whose sum is σ = 1362234163104. Its totient is φ = 1324394325100.

The previous prime is 1343314244057. The next prime is 1343314244141. The reversal of 1343314244101 is 1014424133431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1343314244101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1343314244141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9459959395 + ... + 9459959536.

It is an arithmetic number, because the mean of its divisors is an integer number (340558540776).

Almost surely, 2^{1343314244101} is an apocalyptic number.

It is an amenable number.

1343314244101 is a deficient number, since it is larger than the sum of its proper divisors (18919919003).

1343314244101 is an equidigital number, since it uses as much as digits as its factorization.

1343314244101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18919919002.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1343314244101 its reverse (1014424133431), we get a palindrome (2357738377532).

The spelling of 1343314244101 in words is "one trillion, three hundred forty-three billion, three hundred fourteen million, two hundred forty-four thousand, one hundred one".