Base | Representation |
---|---|
bin | 11001000001010110… |
… | …11101110010100011 |
3 | 1021200011212120220010 |
4 | 30200223131302203 |
5 | 210002342321021 |
6 | 10100543220003 |
7 | 653613015135 |
oct | 144053356243 |
9 | 37604776803 |
10 | 13433167011 |
11 | 5773744220 |
12 | 272a8a7603 |
13 | 1361056944 |
14 | 9160c5055 |
15 | 5394b7976 |
hex | 320addca3 |
13433167011 has 16 divisors (see below), whose sum is σ = 19553448960. Its totient is φ = 8135356320.
The previous prime is 13433166973. The next prime is 13433167037. The reversal of 13433167011 is 11076133431.
13433167011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13433167011 - 29 = 13433166499 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13433167011.
It is not an unprimeable number, because it can be changed into a prime (13433166011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 102931 + ... + 193548.
It is an arithmetic number, because the mean of its divisors is an integer number (1222090560).
Almost surely, 213433167011 is an apocalyptic number.
13433167011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13433167011 is a deficient number, since it is larger than the sum of its proper divisors (6120281949).
13433167011 is a wasteful number, since it uses less digits than its factorization.
13433167011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 297866.
The product of its (nonzero) digits is 4536, while the sum is 30.
The spelling of 13433167011 in words is "thirteen billion, four hundred thirty-three million, one hundred sixty-seven thousand, eleven".
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