Base | Representation |
---|---|
bin | 10011100011000100101… |
… | …101110110100010010111 |
3 | 11202102100222200011110221 |
4 | 103203010231312202113 |
5 | 134002120004304201 |
6 | 2505041203055211 |
7 | 166023654611044 |
oct | 23430455664227 |
9 | 4672328604427 |
10 | 1343330150551 |
11 | 478780938674 |
12 | 19841a671507 |
13 | 998a208768c |
14 | 490361401cb |
15 | 24e22e684a1 |
hex | 138c4b76897 |
1343330150551 has 2 divisors, whose sum is σ = 1343330150552. Its totient is φ = 1343330150550.
The previous prime is 1343330150417. The next prime is 1343330150563. The reversal of 1343330150551 is 1550510333431.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (1550510333431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1343330150551 - 29 = 1343330150039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1343330150051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671665075275 + 671665075276.
It is an arithmetic number, because the mean of its divisors is an integer number (671665075276).
Almost surely, 21343330150551 is an apocalyptic number.
1343330150551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343330150551 is an equidigital number, since it uses as much as digits as its factorization.
1343330150551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40500, while the sum is 34.
Adding to 1343330150551 its reverse (1550510333431), we get a palindrome (2893840483982).
The spelling of 1343330150551 in words is "one trillion, three hundred forty-three billion, three hundred thirty million, one hundred fifty thousand, five hundred fifty-one".
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