Base | Representation |
---|---|
bin | 1100001101111011000100… |
… | …1000100111100101110110 |
3 | 1202120012210011221001120221 |
4 | 3003132301020213211312 |
5 | 3230042432121424032 |
6 | 44323104432044554 |
7 | 2554345360530016 |
oct | 303366110474566 |
9 | 52505704831527 |
10 | 13433334561142 |
11 | 430a055176281 |
12 | 160b57869375a |
13 | 7659b1481c42 |
14 | 346269447c46 |
15 | 1846727d7597 |
hex | c37b1227976 |
13433334561142 has 4 divisors (see below), whose sum is σ = 20150001841716. Its totient is φ = 6716667280570.
The previous prime is 13433334561137. The next prime is 13433334561161. The reversal of 13433334561142 is 24116543333431.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3358333640284 + ... + 3358333640287.
It is an arithmetic number, because the mean of its divisors is an integer number (5037500460429).
Almost surely, 213433334561142 is an apocalyptic number.
13433334561142 is a deficient number, since it is larger than the sum of its proper divisors (6716667280574).
13433334561142 is an equidigital number, since it uses as much as digits as its factorization.
13433334561142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6716667280573.
The product of its digits is 933120, while the sum is 43.
Adding to 13433334561142 its reverse (24116543333431), we get a palindrome (37549877894573).
The spelling of 13433334561142 in words is "thirteen trillion, four hundred thirty-three billion, three hundred thirty-four million, five hundred sixty-one thousand, one hundred forty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.090 sec. • engine limits •