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13434044415647 is a prime number
BaseRepresentation
bin1100001101111101101101…
…1100011111111010011111
31202120021121122122101220112
43003133123130133322133
53230100410332300042
644323303110440235
72554402100303462
oct303373334377237
952507548571815
1013434044415647
11430a389936499
12160b73636307b
13765a955618ab
143462d58292d9
151846b4ca4982
hexc37db71fe9f

13434044415647 has 2 divisors, whose sum is σ = 13434044415648. Its totient is φ = 13434044415646.

The previous prime is 13434044415637. The next prime is 13434044415733. The reversal of 13434044415647 is 74651444043431.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (74651444043431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13434044415647 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13434044415595 and 13434044415604.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13434044415637) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6717022207823 + 6717022207824.

It is an arithmetic number, because the mean of its divisors is an integer number (6717022207824).

Almost surely, 213434044415647 is an apocalyptic number.

13434044415647 is a deficient number, since it is larger than the sum of its proper divisors (1).

13434044415647 is an equidigital number, since it uses as much as digits as its factorization.

13434044415647 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7741440, while the sum is 50.

The spelling of 13434044415647 in words is "thirteen trillion, four hundred thirty-four billion, forty-four million, four hundred fifteen thousand, six hundred forty-seven".