Base | Representation |
---|---|
bin | 1100001101111110001001… |
… | …1110010100101010000100 |
3 | 1202120021220212112021221112 |
4 | 3003133202132110222010 |
5 | 3230101131024144330 |
6 | 44323322522104152 |
7 | 2554405031505656 |
oct | 303374236245204 |
9 | 52507825467845 |
10 | 13434162334340 |
11 | 430a43a456560 |
12 | 160b76994b058 |
13 | 765ab3b0a377 |
14 | 3463073626d6 |
15 | 1846c02e8795 |
hex | c37e2794a84 |
13434162334340 has 24 divisors (see below), whose sum is σ = 30776444620992. Its totient is φ = 4885149939680.
The previous prime is 13434162334289. The next prime is 13434162334381. The reversal of 13434162334340 is 4343326143431.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30532186904 + ... + 30532187343.
It is an arithmetic number, because the mean of its divisors is an integer number (1282351859208).
Almost surely, 213434162334340 is an apocalyptic number.
13434162334340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13434162334340 is an abundant number, since it is smaller than the sum of its proper divisors (17342282286652).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13434162334340 is a wasteful number, since it uses less digits than its factorization.
13434162334340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61064374267 (or 61064374265 counting only the distinct ones).
The product of its (nonzero) digits is 746496, while the sum is 41.
Adding to 13434162334340 its reverse (4343326143431), we get a palindrome (17777488477771).
The spelling of 13434162334340 in words is "thirteen trillion, four hundred thirty-four billion, one hundred sixty-two million, three hundred thirty-four thousand, three hundred forty".
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