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134343151 = 1109121139
BaseRepresentation
bin10000000000111…
…10100111101111
3100100210100011021
420000132213233
5233342440101
621155235011
73220616665
oct1000364757
9310710137
10134343151
1169918aa8
1238ba8a67
1321aa95b7
1413bb0c35
15bbda5a1
hex801e9ef

134343151 has 4 divisors (see below), whose sum is σ = 134465400. Its totient is φ = 134220904.

The previous prime is 134343149. The next prime is 134343169. The reversal of 134343151 is 151343431.

134343151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134343151 - 21 = 134343149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134349151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59461 + ... + 61678.

It is an arithmetic number, because the mean of its divisors is an integer number (33616350).

Almost surely, 2134343151 is an apocalyptic number.

134343151 is a deficient number, since it is larger than the sum of its proper divisors (122249).

134343151 is a wasteful number, since it uses less digits than its factorization.

134343151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 122248.

The product of its digits is 2160, while the sum is 25.

The square root of 134343151 is about 11590.6492915626. The cubic root of 134343151 is about 512.1594339397.

Adding to 134343151 its reverse (151343431), we get a palindrome (285686582).

The spelling of 134343151 in words is "one hundred thirty-four million, three hundred forty-three thousand, one hundred fifty-one".

Divisors: 1 1109 121139 134343151