Base | Representation |
---|---|
bin | 10011100011001011010… |
… | …001110001111111011101 |
3 | 11202102122122210220101221 |
4 | 103203023101301333131 |
5 | 134002331144414123 |
6 | 2505100134333341 |
7 | 166026462363316 |
oct | 23431321617735 |
9 | 4672578726357 |
10 | 1343440232413 |
11 | 478827a95814 |
12 | 19844b4ba251 |
13 | 998bbb1b086 |
14 | 490469d760d |
15 | 24e2c96025d |
hex | 138cb471fdd |
1343440232413 has 2 divisors, whose sum is σ = 1343440232414. Its totient is φ = 1343440232412.
The previous prime is 1343440232411. The next prime is 1343440232419. The reversal of 1343440232413 is 3142320443431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 903311482329 + 440128750084 = 950427^2 + 663422^2 .
It is a cyclic number.
It is not a de Polignac number, because 1343440232413 - 21 = 1343440232411 is a prime.
Together with 1343440232411, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1343440232411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671720116206 + 671720116207.
It is an arithmetic number, because the mean of its divisors is an integer number (671720116207).
Almost surely, 21343440232413 is an apocalyptic number.
It is an amenable number.
1343440232413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343440232413 is an equidigital number, since it uses as much as digits as its factorization.
1343440232413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 1343440232413 its reverse (3142320443431), we get a palindrome (4485760675844).
The spelling of 1343440232413 in words is "one trillion, three hundred forty-three billion, four hundred forty million, two hundred thirty-two thousand, four hundred thirteen".
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