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134355444343 = 367366091129
BaseRepresentation
bin111110100100000110…
…1010110001001110111
3110211210110110202001021
41331020031112021313
54200124443204333
6141415543242011
712464311301551
oct1751015261167
9424713422037
10134355444343
1151a86166a0a
1222057449307
13c892337533
146707b064d1
1537653ea82d
hex1f48356277

134355444343 has 4 divisors (see below), whose sum is σ = 134721535840. Its totient is φ = 133989352848.

The previous prime is 134355444269. The next prime is 134355444367. The reversal of 134355444343 is 343444553431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134355444343 - 213 = 134355436151 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 134355444343.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134355444943) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183045198 + ... + 183045931.

It is an arithmetic number, because the mean of its divisors is an integer number (33680383960).

Almost surely, 2134355444343 is an apocalyptic number.

134355444343 is a deficient number, since it is larger than the sum of its proper divisors (366091497).

134355444343 is an equidigital number, since it uses as much as digits as its factorization.

134355444343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 366091496.

The product of its digits is 2073600, while the sum is 43.

Adding to 134355444343 its reverse (343444553431), we get a palindrome (477799997774).

The spelling of 134355444343 in words is "one hundred thirty-four billion, three hundred fifty-five million, four hundred forty-four thousand, three hundred forty-three".

Divisors: 1 367 366091129 134355444343