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134365441040113 = 643446881467611
BaseRepresentation
bin11110100011010001100100…
…011000100001111011110001
3122121202012200121111022001111
4132203101210120201323301
5120102420410401240423
61153434344221433321
740205403613253533
oct3643214430417361
9577665617438044
10134365441040113
11398a4077627118
12130a0b0a40b841
1359c87b6c7895a
14252747199d853
151080247e8a60d
hex7a3464621ef1

134365441040113 has 8 divisors (see below), whose sum is σ = 134574996444896. Its totient is φ = 134155887465600.

The previous prime is 134365441040059. The next prime is 134365441040137. The reversal of 134365441040113 is 311040144563431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134365441040113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134365441046113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 287110678 + ... + 287578288.

It is an arithmetic number, because the mean of its divisors is an integer number (16821874555612).

Almost surely, 2134365441040113 is an apocalyptic number.

It is an amenable number.

134365441040113 is a deficient number, since it is larger than the sum of its proper divisors (209555404783).

134365441040113 is an equidigital number, since it uses as much as digits as its factorization.

134365441040113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 915135.

The product of its (nonzero) digits is 207360, while the sum is 40.

The spelling of 134365441040113 in words is "one hundred thirty-four trillion, three hundred sixty-five billion, four hundred forty-one million, forty thousand, one hundred thirteen".

Divisors: 1 643 446881 467611 287344483 300673873 208966471291 134365441040113