Base | Representation |
---|---|
bin | 11001000010001011… |
… | …11010011110110001 |
3 | 1021200122220211112121 |
4 | 30201011322132301 |
5 | 210011131202043 |
6 | 10101351554241 |
7 | 654025652545 |
oct | 144105723661 |
9 | 37618824477 |
10 | 13440100273 |
11 | 577764a296 |
12 | 273108b981 |
13 | 1362613672 |
14 | 916daba25 |
15 | 539dd6ded |
hex | 32117a7b1 |
13440100273 has 2 divisors, whose sum is σ = 13440100274. Its totient is φ = 13440100272.
The previous prime is 13440100099. The next prime is 13440100279. The reversal of 13440100273 is 37200104431.
13440100273 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9268490529 + 4171609744 = 96273^2 + 64588^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13440100273 is a prime.
It is not a weakly prime, because it can be changed into another prime (13440100279) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720050136 + 6720050137.
It is an arithmetic number, because the mean of its divisors is an integer number (6720050137).
Almost surely, 213440100273 is an apocalyptic number.
It is an amenable number.
13440100273 is a deficient number, since it is larger than the sum of its proper divisors (1).
13440100273 is an equidigital number, since it uses as much as digits as its factorization.
13440100273 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 25.
The spelling of 13440100273 in words is "thirteen billion, four hundred forty million, one hundred thousand, two hundred seventy-three".
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