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134401119949 is a prime number
BaseRepresentation
bin111110100101011101…
…1100101011011001101
3110211220122102022012101
41331022323211123031
54200223141314244
6141424254235101
712465404445565
oct1751273453315
9424818368171
10134401119949
1151aa9a23748
122206a7b5a91
13c89b93a515
14670dbd5da5
15376941e0d4
hex1f4aee56cd

134401119949 has 2 divisors, whose sum is σ = 134401119950. Its totient is φ = 134401119948.

The previous prime is 134401119929. The next prime is 134401119997. The reversal of 134401119949 is 949911104431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 83333255625 + 51067864324 = 288675^2 + 225982^2 .

It is a cyclic number.

It is not a de Polignac number, because 134401119949 - 211 = 134401117901 is a prime.

It is a super-2 number, since 2×1344011199492 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134401119899 and 134401119908.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134401119929) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67200559974 + 67200559975.

It is an arithmetic number, because the mean of its divisors is an integer number (67200559975).

Almost surely, 2134401119949 is an apocalyptic number.

It is an amenable number.

134401119949 is a deficient number, since it is larger than the sum of its proper divisors (1).

134401119949 is an equidigital number, since it uses as much as digits as its factorization.

134401119949 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 139968, while the sum is 46.

The spelling of 134401119949 in words is "one hundred thirty-four billion, four hundred one million, one hundred nineteen thousand, nine hundred forty-nine".