134401119999 has 4 divisors (see below), whose sum is σ = 179201493336. Its totient is φ = 89600746664.

The previous prime is 134401119997. The next prime is 134401120033. The reversal of 134401119999 is 999911104431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 999911104431 = 3 ⋅333303701477.

It is a cyclic number.

It is not a de Polignac number, because 134401119999 - 2¹ = 134401119997 is a prime.

It is a super-2 number, since 2×134401119999² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134401119997) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22400186664 + ... + 22400186669.

It is an arithmetic number, because the mean of its divisors is an integer number (44800373334).

Almost surely, 2^134401119999 is an apocalyptic number.

134401119999 is a deficient number, since it is larger than the sum of its proper divisors (44800373337).

134401119999 is an equidigital number, since it uses as much as digits as its factorization.

134401119999 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44800373336.

The product of its (nonzero) digits is 314928, while the sum is 51.

The spelling of 134401119999 in words is "one hundred thirty-four billion, four hundred one million, one hundred nineteen thousand, nine hundred ninety-nine".