134401120000 has 720 divisors, whose sum is σ = 408669184000. Its totient is φ = 44029440000.

The previous prime is 134401119997. The next prime is 134401120033. The reversal of 134401120000 is 21104431.

It is a super-2 number, since 2×134401120000² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 1701279961 + ... + 1701280039.

Almost surely, 2^134401120000 is an apocalyptic number.

134401120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134401120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (204334592000).

134401120000 is an abundant number, since it is smaller than the sum of its proper divisors (274268064000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134401120000 is an frugal number, since it uses more digits than its factorization.

134401120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 167 (or 124 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 134401120000 its reverse (21104431), we get a palindrome (134422224431).

The spelling of 134401120000 in words is "one hundred thirty-four billion, four hundred one million, one hundred twenty thousand".