134401120013 has 4 divisors (see below), whose sum is σ = 134407822428. Its totient is φ = 134394417600.

The previous prime is 134401119997. The next prime is 134401120033. The reversal of 134401120013 is 310021104431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 310021104431 = 761 ⋅407386471.

It can be written as a sum of positive squares in 2 ways, for example, as 61542694084 + 72858425929 = 248078^2 + 269923^2 .

It is a cyclic number.

It is not a de Polignac number, because 134401120013 - 2⁴ = 134401119997 is a prime.

It is a super-2 number, since 2×134401120013² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134401120033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3321038 + ... + 3361263.

It is an arithmetic number, because the mean of its divisors is an integer number (33601955607).

Almost surely, 2^134401120013 is an apocalyptic number.

It is an amenable number.

134401120013 is a deficient number, since it is larger than the sum of its proper divisors (6702415).

134401120013 is an equidigital number, since it uses as much as digits as its factorization.

134401120013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6702414.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 134401120013 its reverse (310021104431), we get a palindrome (444422224444).

The spelling of 134401120013 in words is "one hundred thirty-four billion, four hundred one million, one hundred twenty thousand, thirteen".