134401120032 has 24 divisors (see below), whose sum is σ = 352802940336. Its totient is φ = 44800373312.

The previous prime is 134401119997. The next prime is 134401120033. The reversal of 134401120032 is 230021104431.

It is a tau number, because it is divible by the number of its divisors (24).

It is a super-2 number, since 2×134401120032² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134401119990 and 134401120008.

It is not an unprimeable number, because it can be changed into a prime (134401120033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 700005738 + ... + 700005929.

It is an arithmetic number, because the mean of its divisors is an integer number (14700122514).

Almost surely, 2^134401120032 is an apocalyptic number.

134401120032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

134401120032 is an abundant number, since it is smaller than the sum of its proper divisors (218401820304).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134401120032 is a wasteful number, since it uses less digits than its factorization.

134401120032 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1400011680 (or 1400011672 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 134401120032 its reverse (230021104431), we get a palindrome (364422224463).

The spelling of 134401120032 in words is "one hundred thirty-four billion, four hundred one million, one hundred twenty thousand, thirty-two".