Base | Representation |
---|---|
bin | 10011100011101101010… |
… | …011111100100111001111 |
3 | 11202111010110020100201221 |
4 | 103203231103330213033 |
5 | 134010013333204201 |
6 | 2505232532544211 |
7 | 166046564631331 |
oct | 23435523744717 |
9 | 4674113210657 |
10 | 1344011225551 |
11 | 478aa0331375 |
12 | 19858a782067 |
13 | 999801cba37 |
14 | 4909c78d451 |
15 | 24e62b4d4a1 |
hex | 138ed4fc9cf |
1344011225551 has 2 divisors, whose sum is σ = 1344011225552. Its totient is φ = 1344011225550.
The previous prime is 1344011225539. The next prime is 1344011225591. The reversal of 1344011225551 is 1555221104431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1344011225551 - 25 = 1344011225519 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344011225591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672005612775 + 672005612776.
It is an arithmetic number, because the mean of its divisors is an integer number (672005612776).
Almost surely, 21344011225551 is an apocalyptic number.
1344011225551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344011225551 is an equidigital number, since it uses as much as digits as its factorization.
1344011225551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24000, while the sum is 34.
Adding to 1344011225551 its reverse (1555221104431), we get a palindrome (2899232329982).
The spelling of 1344011225551 in words is "one trillion, three hundred forty-four billion, eleven million, two hundred twenty-five thousand, five hundred fifty-one".
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