Base | Representation |
---|---|
bin | 10011100011101101010… |
… | …011111100100111000011 |
3 | 11202111010110020100201111 |
4 | 103203231103330213003 |
5 | 134010013333204124 |
6 | 2505232532544151 |
7 | 166046564631313 |
oct | 23435523744703 |
9 | 4674113210644 |
10 | 1344011225539 |
11 | 478aa0331364 |
12 | 19858a782057 |
13 | 999801cba28 |
14 | 4909c78d443 |
15 | 24e62b4d494 |
hex | 138ed4fc9c3 |
1344011225539 has 2 divisors, whose sum is σ = 1344011225540. Its totient is φ = 1344011225538.
The previous prime is 1344011225533. The next prime is 1344011225551. The reversal of 1344011225539 is 9355221104431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1344011225539 - 223 = 1344002836931 is a prime.
It is not a weakly prime, because it can be changed into another prime (1344011225533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672005612769 + 672005612770.
It is an arithmetic number, because the mean of its divisors is an integer number (672005612770).
Almost surely, 21344011225539 is an apocalyptic number.
1344011225539 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344011225539 is an equidigital number, since it uses as much as digits as its factorization.
1344011225539 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 40.
The spelling of 1344011225539 in words is "one trillion, three hundred forty-four billion, eleven million, two hundred twenty-five thousand, five hundred thirty-nine".
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