Base | Representation |
---|---|
bin | 1100001110010100010110… |
… | …1001001110011101000111 |
3 | 1202120212022011000011111111 |
4 | 3003211011221032131013 |
5 | 3230200332000313244 |
6 | 44330150103145451 |
7 | 2555005505303566 |
oct | 303450551163507 |
9 | 52525264004444 |
10 | 13440121104199 |
11 | 4311a17a86549 |
12 | 1610951445287 |
13 | 76652349b6aa |
14 | 3467108bbbdd |
15 | 18491d4d9e34 |
hex | c3945a4e747 |
13440121104199 has 2 divisors, whose sum is σ = 13440121104200. Its totient is φ = 13440121104198.
The previous prime is 13440121104167. The next prime is 13440121104227. The reversal of 13440121104199 is 99140112104431.
13440121104199 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13440121104199 - 25 = 13440121104167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13440121104149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720060552099 + 6720060552100.
It is an arithmetic number, because the mean of its divisors is an integer number (6720060552100).
Almost surely, 213440121104199 is an apocalyptic number.
13440121104199 is a deficient number, since it is larger than the sum of its proper divisors (1).
13440121104199 is an equidigital number, since it uses as much as digits as its factorization.
13440121104199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 40.
The spelling of 13440121104199 in words is "thirteen trillion, four hundred forty billion, one hundred twenty-one million, one hundred four thousand, one hundred ninety-nine".
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