13440121104227 has 2 divisors, whose sum is σ = 13440121104228. Its totient is φ = 13440121104226.

The previous prime is 13440121104199. The next prime is 13440121104229. The reversal of 13440121104227 is 72240112104431.

13440121104227 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13440121104227 - 2²⁴ = 13440104327011 is a prime.

Together with 13440121104229, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13440121104193 and 13440121104202.

It is not a weakly prime, because it can be changed into another prime (13440121104229) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720060552113 + 6720060552114.

It is an arithmetic number, because the mean of its divisors is an integer number (6720060552114).

Almost surely, 2^{13440121104227} is an apocalyptic number.

13440121104227 is a deficient number, since it is larger than the sum of its proper divisors (1).

13440121104227 is an equidigital number, since it uses as much as digits as its factorization.

13440121104227 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10752, while the sum is 32.

Adding to 13440121104227 its reverse (72240112104431), we get a palindrome (85680233208658).

The spelling of 13440121104227 in words is "thirteen trillion, four hundred forty billion, one hundred twenty-one million, one hundred four thousand, two hundred twenty-seven".