1344021311 has 2 divisors, whose sum is σ = 1344021312. Its totient is φ = 1344021310.

The previous prime is 1344021299. The next prime is 1344021317. The reversal of 1344021311 is 1131204431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1344021311 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1344021317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672010655 + 672010656.

It is an arithmetic number, because the mean of its divisors is an integer number (672010656).

Almost surely, 2^1344021311 is an apocalyptic number.

1344021311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344021311 is an equidigital number, since it uses as much as digits as its factorization.

1344021311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

The square root of 1344021311 is about 36660.8962110857. The cubic root of 1344021311 is about 1103.5755034019.

Adding to 1344021311 its reverse (1131204431), we get a palindrome (2475225742).

The spelling of 1344021311 in words is "one billion, three hundred forty-four million, twenty-one thousand, three hundred eleven".