13440220331 has 4 divisors (see below), whose sum is σ = 13445105112. Its totient is φ = 13435335552.

The previous prime is 13440220319. The next prime is 13440220333. The reversal of 13440220331 is 13302204431.

13440220331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13302204431 = 1163 ⋅11437837.

It is a cyclic number.

It is not a de Polignac number, because 13440220331 - 2¹⁴ = 13440203947 is a prime.

It is a super-2 number, since 2×13440220331² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13440220297 and 13440220306.

It is not an unprimeable number, because it can be changed into a prime (13440220333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2438261 + ... + 2443766.

It is an arithmetic number, because the mean of its divisors is an integer number (3361276278).

Almost surely, 2^13440220331 is an apocalyptic number.

13440220331 is a deficient number, since it is larger than the sum of its proper divisors (4884781).

13440220331 is an equidigital number, since it uses as much as digits as its factorization.

13440220331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4884780.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 13440220331 its reverse (13302204431), we get a palindrome (26742424762).

The spelling of 13440220331 in words is "thirteen billion, four hundred forty million, two hundred twenty thousand, three hundred thirty-one".