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13440225445 = 557714713167
BaseRepresentation
bin11001000010001100…
…11001000010100101
31021200200011012020121
430201012121002211
5210011144203240
610101354401541
7654030013513
oct144106310245
937620135217
1013440225445
115777725339
1227311302b1
13136265862a
149170014b3
15539e0e04a
hex3211990a5

13440225445 has 16 divisors (see below), whose sum is σ = 16172310528. Its totient is φ = 10722862080.

The previous prime is 13440225419. The next prime is 13440225481. The reversal of 13440225445 is 54452204431.

It is not a de Polignac number, because 13440225445 - 215 = 13440192677 is a prime.

It is a super-3 number, since 3×134402254453 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13440225445.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4242252 + ... + 4245418.

It is an arithmetic number, because the mean of its divisors is an integer number (1010769408).

Almost surely, 213440225445 is an apocalyptic number.

It is an amenable number.

13440225445 is a deficient number, since it is larger than the sum of its proper divisors (2732085083).

13440225445 is a wasteful number, since it uses less digits than its factorization.

13440225445 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5220.

The product of its (nonzero) digits is 76800, while the sum is 34.

Adding to 13440225445 its reverse (54452204431), we get a palindrome (67892429876).

The spelling of 13440225445 in words is "thirteen billion, four hundred forty million, two hundred twenty-five thousand, four hundred forty-five".

Divisors: 1 5 577 1471 2885 3167 7355 15835 848767 1827359 4243835 4658657 9136795 23293285 2688045089 13440225445