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13440231214310 = 252161162191621
BaseRepresentation
bin1100001110010100110000…
…1101010000110011100110
31202120212120211012100011202
43003211030031100303212
53230201043142324220
644330205035202502
72555011313234405
oct303451415206346
952525524170152
1013440231214310
114311a7415293a
1216109822a6432
13766540241bc4
1434672138163c
15184927eda275
hexc394c350ce6

13440231214310 has 16 divisors (see below), whose sum is σ = 24193536023952. Its totient is φ = 5375843632800.

The previous prime is 13440231214307. The next prime is 13440231214367. The reversal of 13440231214310 is 1341213204431.

It is a super-2 number, since 2×134402312143102 (a number of 27 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30879701 + ... + 31311920.

It is an arithmetic number, because the mean of its divisors is an integer number (1512096001497).

Almost surely, 213440231214310 is an apocalyptic number.

13440231214310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13440231214310 is a deficient number, since it is larger than the sum of its proper divisors (10753304809642).

13440231214310 is a wasteful number, since it uses less digits than its factorization.

13440231214310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62213239.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13440231214310 its reverse (1341213204431), we get a palindrome (14781444418741).

The spelling of 13440231214310 in words is "thirteen trillion, four hundred forty billion, two hundred thirty-one million, two hundred fourteen thousand, three hundred ten".

Divisors: 1 2 5 10 21611 43222 108055 216110 62191621 124383242 310958105 621916210 1344023121431 2688046242862 6720115607155 13440231214310