13440402103 has 2 divisors, whose sum is σ = 13440402104. Its totient is φ = 13440402102.

The previous prime is 13440402013. The next prime is 13440402127. The reversal of 13440402103 is 30120404431.

Together with previous prime (13440402013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13440402103 - 2²⁹ = 12903531191 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13440408103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720201051 + 6720201052.

It is an arithmetic number, because the mean of its divisors is an integer number (6720201052).

Almost surely, 2^13440402103 is an apocalyptic number.

13440402103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13440402103 is an equidigital number, since it uses as much as digits as its factorization.

13440402103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 13440402103 its reverse (30120404431), we get a palindrome (43560806534).

The spelling of 13440402103 in words is "thirteen billion, four hundred forty million, four hundred two thousand, one hundred three".