13440402013 has 2 divisors, whose sum is σ = 13440402014. Its totient is φ = 13440402012.

The previous prime is 13440401993. The next prime is 13440402103. The reversal of 13440402013 is 31020404431.

Together with next prime (13440402103) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13056947289 + 383454724 = 114267^2 + 19582^2 .

It is a cyclic number.

It is not a de Polignac number, because 13440402013 - 2⁵ = 13440401981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13440403013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720201006 + 6720201007.

It is an arithmetic number, because the mean of its divisors is an integer number (6720201007).

Almost surely, 2^13440402013 is an apocalyptic number.

It is an amenable number.

13440402013 is a deficient number, since it is larger than the sum of its proper divisors (1).

13440402013 is an equidigital number, since it uses as much as digits as its factorization.

13440402013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 13440402013 its reverse (31020404431), we get a palindrome (44460806444).

The spelling of 13440402013 in words is "thirteen billion, four hundred forty million, four hundred two thousand, thirteen".