1344044234121 has 4 divisors (see below), whose sum is σ = 1792058978832. Its totient is φ = 896029489412.

The previous prime is 1344044234077. The next prime is 1344044234131. The reversal of 1344044234121 is 1214324404431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1344044234121 - 2¹³ = 1344044225929 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1344044234131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224007372351 + ... + 224007372356.

It is an arithmetic number, because the mean of its divisors is an integer number (448014744708).

Almost surely, 2^{1344044234121} is an apocalyptic number.

It is an amenable number.

1344044234121 is a deficient number, since it is larger than the sum of its proper divisors (448014744711).

1344044234121 is an equidigital number, since it uses as much as digits as its factorization.

1344044234121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 448014744710.

The product of its (nonzero) digits is 36864, while the sum is 33.

Adding to 1344044234121 its reverse (1214324404431), we get a palindrome (2558368638552).

The spelling of 1344044234121 in words is "one trillion, three hundred forty-four billion, forty-four million, two hundred thirty-four thousand, one hundred twenty-one".