Search a number
-
+
13441101432214 = 26720550716107
BaseRepresentation
bin1100001110011000000000…
…0100111000010110010110
31202120221211110122222201111
43003212000010320112112
53230204333431312324
644330431243045234
72555042011043011
oct303460004702626
952527743588644
1013441101432214
114312380393495
121610b8581081a
1376664b60b841
143467a4b88378
151849795d2794
hexc3980138596

13441101432214 has 4 divisors (see below), whose sum is σ = 20161652148324. Its totient is φ = 6720550716106.

The previous prime is 13441101432151. The next prime is 13441101432223. The reversal of 13441101432214 is 41223410114431.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×134411014322142 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3360275358052 + ... + 3360275358055.

It is an arithmetic number, because the mean of its divisors is an integer number (5040413037081).

Almost surely, 213441101432214 is an apocalyptic number.

13441101432214 is a deficient number, since it is larger than the sum of its proper divisors (6720550716110).

13441101432214 is an equidigital number, since it uses as much as digits as its factorization.

13441101432214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6720550716109.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 13441101432214 its reverse (41223410114431), we get a palindrome (54664511546645).

The spelling of 13441101432214 in words is "thirteen trillion, four hundred forty-one billion, one hundred one million, four hundred thirty-two thousand, two hundred fourteen".

Divisors: 1 2 6720550716107 13441101432214