13441121023 has 4 divisors (see below), whose sum is σ = 14663041128. Its totient is φ = 12219200920.

The previous prime is 13441121003. The next prime is 13441121047. The reversal of 13441121023 is 32012114431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13441121023 - 2⁵ = 13441120991 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13441120985 and 13441121003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13441121003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 610960036 + ... + 610960057.

It is an arithmetic number, because the mean of its divisors is an integer number (3665760282).

Almost surely, 2^13441121023 is an apocalyptic number.

13441121023 is a deficient number, since it is larger than the sum of its proper divisors (1221920105).

13441121023 is a wasteful number, since it uses less digits than its factorization.

13441121023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1221920104.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 13441121023 its reverse (32012114431), we get a palindrome (45453235454).

The spelling of 13441121023 in words is "thirteen billion, four hundred forty-one million, one hundred twenty-one thousand, twenty-three".