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13441126841305 = 58147329965063
BaseRepresentation
bin1100001110011000000110…
…0101110011101111011001
31202120221220020110220102221
43003212001211303233121
53230204411432410210
644330433551424041
72555042440031002
oct303460145635731
952527806426387
1013441126841305
114312393768739
121610b92225021
13766653966cc7
143467a82c01a9
1518497b9511da
hexc3981973bd9

13441126841305 has 8 divisors (see below), whose sum is σ = 16131332048832. Its totient is φ = 10751581580208.

The previous prime is 13441126841299. The next prime is 13441126841333. The reversal of 13441126841305 is 50314862114431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13441126841305 - 215 = 13441126808537 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 164941797 + ... + 165023266.

It is an arithmetic number, because the mean of its divisors is an integer number (2016416506104).

Almost surely, 213441126841305 is an apocalyptic number.

It is an amenable number.

13441126841305 is a deficient number, since it is larger than the sum of its proper divisors (2690205207527).

13441126841305 is an equidigital number, since it uses as much as digits as its factorization.

13441126841305 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 329973215.

The product of its (nonzero) digits is 276480, while the sum is 43.

Adding to 13441126841305 its reverse (50314862114431), we get a palindrome (63755988955736).

The spelling of 13441126841305 in words is "thirteen trillion, four hundred forty-one billion, one hundred twenty-six million, eight hundred forty-one thousand, three hundred five".

Divisors: 1 5 8147 40735 329965063 1649825315 2688225368261 13441126841305