13442043405541 has 4 divisors (see below), whose sum is σ = 13495597363584. Its totient is φ = 13388489447500.

The previous prime is 13442043405529. The next prime is 13442043405551. The reversal of 13442043405541 is 14550434024431.

13442043405541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13442043405541 - 2¹⁷ = 13442043274469 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13442043405494 and 13442043405503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13442043405551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26776978645 + ... + 26776979146.

It is an arithmetic number, because the mean of its divisors is an integer number (3373899340896).

Almost surely, 2^{13442043405541} is an apocalyptic number.

It is an amenable number.

13442043405541 is a deficient number, since it is larger than the sum of its proper divisors (53553958043).

13442043405541 is an equidigital number, since it uses as much as digits as its factorization.

13442043405541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53553958042.

The product of its (nonzero) digits is 460800, while the sum is 40.

Adding to 13442043405541 its reverse (14550434024431), we get a palindrome (27992477429972).

The spelling of 13442043405541 in words is "thirteen trillion, four hundred forty-two billion, forty-three million, four hundred five thousand, five hundred forty-one".